Question

A 30 mL solution contains 5.2 g NaNO2. Calculate the molarity of the solution

Answer 1

The molarity of the solution containing 5.2 g of NaNO2 in 30 mL of solution is calculated to be 2.51 M, using the molar mass of NaNO2 and converting the volume of the solution to liters.

Step-by-step explanation:

To calculate the molarity of a solution, we use the formula:

M = moles of solute / liters of solution

First, we need to convert the given mass of NaNO2 into moles. The molar mass of NaNO2 is approximately 69.00 g/mol. Using this molar mass:

moles of NaNO2 = 5.2 g / 69.00 g/mol = 0.0754 mol

Then we convert the volume of the solution from mL to L:

volume of solution = 30 mL = 0.030 L

Now, we can find the molarity of the solution:

M = 0.0754 mol / 0.030 L

M = 2.51 M

The molarity of the NaNO2 solution is 2.51 M.

Answer 2

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