Question

Find the equation of a line that contains the points (−4,8) and (7,−6). Use fractions in your response, not decimals.

Answer 1

Explanation:

Equation of line in slope y-intercept form:

(-4,8) ; x₁ = -4 & y₁ = 8

(7,-6) ; x₂ = 7 & y₂ = -6

`\sf \boxed{Slope=(y_2-y_1)/(x_2-x_1)}`

`\sf =(-6-8)/(7-[-4])\\\\ =(-14)/(7+4)\\\\=(-14)/(11)`

Equation of line:

`\sf y-y_1=m(x-x_1)`

`y - 8 = (-14)/(11)(x -[-4])\\\\y- 8 = (-14)/(11)(x+4)\\\\y -8 = (-14)/(11)x-(14*4)/(11)\\\\ y = (-14)/(11)x-(56)/(11)+8\\\\ y =(-14)/(11)x-(56)/(11)+(88)/(11)\\\\y=(-14)/(11)x+(32)/(11)`