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Write the vertex form of y=4x^2+16x-48

User Asi Givati
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1 Answer

11 votes
11 votes

Answer:

the vertex form :

4(x − (-2))² - 64

Explanation:

4x²+16x-48

= 4(x² + 4x) - 48

= 4(x² + 4x + 4 - 4) - 48

= 4(x² + 4x + 4) - 4×4 - 48

= 4(x + 2)² - 16 - 48

= 4(x + 2)² - (16 + 48)

= 4(x + 2)² - 64

= 4(x − (-2))² - 64

User Brad Cannell
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