Question

Find the equation of the line shown.

y
3
2
2
3
5
2
2 3 4 5

Answer 1

Answer:
`y=(1)/(2)x+(1)/(2)`

Explanation:

The line passes through (-1, 0) and (3,2), so the gradient is
`(2-0)/(3-(-1))=(1)/(2)`.

This means the equation of the line is of the form
`y=(1)/(2)x+c` for some constant c.

Substituting in the coordinates of the point (-1,0),

`0=(1)/(2)(-1)+c\\\\0=-(1)/(2)+c\\ \\ c=(1)/(2)`

Thus, the equation of the line is
`y=(1)/(2)x+(1)/(2)`