If Candace decides to buy breakfast for $9. 90 and 3 pounds of Dark Roast coffee, the largest whole number that x can be is 14
What are the possible values?
The possible values of x are: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 when she buy 1-pound bags of the Morning Blend coffee . Let the number of whole 1-pound bags of the Morning Blend coffee be x.
Candace decides to buy breakfast for $9.90 and 3 pounds of Dark Roast coffee.
Hence, the cost of breakfast and 3 pounds of Dark Roast coffee
= $9.90 + 3x
As she could also buy Morning Blend coffee with her $52,
it means she has $52 − $9.90 − 3x
= $42.10 − 3x remaining to buy Morning Blend coffee.
Hence, we need to find all possible integral values of x, such that the following is satisfied: 42.10 - 3x ≥ 0
Because if this inequality isn't satisfied, she won't have enough money to buy any of the Morning Blend coffee. Breaking this inequality into parts:
42.10 - 3x ≥ 0
⇒ - 3x ≥ - 42.10
⇒ 3x ≤ 42.10
⇒ x ≤ 14.03.
So, the largest whole number that x can be is 14
Complete question is:
If Candace decides to buy breakfast for $9. 90 and 3 pounds of Dark Roast coffee, what are all possible values for the number of WHOLE 1-pound bags of the Morning Blend coffee that she could also buy with her $52?