24.9k views
0 votes
A ball at the end of a 2 meter string revolves in a circle at a rate of 4 m/s. What

is the centripetal acceleration of the ball?

1 Answer

4 votes

Answer:

8 m/s^2

Explanation:

You can use the equation a = v^2 / r

That is acceleration is equal to velocity squared divided by the radius which in this problem is the length of the string. The velocity is 4m/s and the r the radius is 2 m. Now you can square 4 m/s to get 16 m^2/s^2 THEN you divide by 2 m and the m^2 turns to just m and the 16 to an 8. So, that leaves you with acceleration or in this case centripetal acceleration equals 8 m/s^2.

a = 8 m/s^2 or 8 meters per second squared.

User Phreakhead
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories