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Find the center (h,k) and radius r of the circle with the given equation.

3(x+2)² +3(y-5)² = 108

1 Answer

3 votes

Answer: Center (-2,5) and radius 6

Explanation:

Dividing both sides by 3, we get
(x+2)^2 + (y-5)^2 = 36

So, the center is (-2,5) and the radius is
√(36)=\boxed{6}

Find the center (h,k) and radius r of the circle with the given equation. 3(x+2)² +3(y-example-1
User Bazon
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