Question

How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas

measured at STP?
CO2(g)
+ 2 NaOH(aq)
Na2 CO3(aq) + H2Oa)

Answer 1

Volume of NaOH required to react = 145.5 ml

Further explanation

Reaction

CO₂(g) + 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

`\tt mol~CO_2=(0.45)/(22.4)=0.02`

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

`\tt mol~NaOH=(2)/(1)* 0.02=0.04`

Then volume of NaOH :

`\tt V=(n)/(M)\\\\V=(0.04)/(0.275)\\\\V=0.1455~L\rightarrow 145.5~mL`