Question

A small light bulb is connected to a 20 V battery and draws 1.25 A of current. What is the net resistance of the bulb? *

Answer 1

The net resistance of the bulb : 16 Ω

Further explanation

Electric current (symbolized by the letter "i) is the amount of charge flowing in the conductor of each unit of time

Can be formulated:

`\large{\boxed{\bold{I=(Q)/(t)}}`

Q = charge (Coulomb)

t = time (seconds)

The international standard unit of electric current is Coulomb/second or Ampere (A).

Electric current is also a ratio between the voltage and the amount of resistance at the conductor.

Can be formulated

`\large{\boxed{\bold{I=(V)/(R)}}`

V = Voltage (volts)

R = resistance (ohms)

This formula is also known as Ohm's Law

A small light bulb is connected to a 20 V battery and draws 1.25 A of current, so,

`\tt V=20~V\\\\I=2.5~A`

the resistance :

`\tt R=(V)/(I)\\\\R=(20)/(1.25)\\\\R=16~ohm`