Question

A student connects three AA batteries (1.5 V each) in series to light up a light bulb. The circuit has a resistance of 35 Ω. How much current flows through the circuit?

A.
52.5 A

B.
0.13 A

C.
157.5 A

D.
0.04 A

Answer 1

0.13A

Step-by-step explanation:

Given parameters:

Number of batteries = 3

Voltage of each batter = 1.5V

Voltage of the circuit = 3 x 1.5 = 4.5V

Resistance = 35Ω

Unknown:

Current that flows in the circuit = ?

Solution:

According to Ohm's law;

I =
`(V)/(R)`

I is the current

V is the voltage

R is the resistance

Now insert the parameters and solve;

I =
`(4.5)/(35)` = 0.13A