Answer:
Q = -64893.84 J
Step-by-step explanation:
Given data:
Mass of steam = 110 g
Initial temperature = 181 °C
Final temperature = 40°C
Energy released = ?
Solution:
Energy will released in this process because temperature is going to be decreased.
Specific heat capacity of water is 4.184 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40°C - 181 °C
ΔT = -141°C
Q = 110 g × 4.184 J/g.°C × -141°C
Q = -64893.84 J