Question

How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water has a specific heat of 4,190 J/kg °C.

Answer 1

73325J

Step-by-step explanation:

Given parameters:

Mass of water = 0.5kg

Initial temperature = 30°C

Final temperature = 65°C

Specific heat capacity = 4190J/kg°C

Unknown:

Amount of energy absorbed = ?

Solution:

The amount of energy absorbed can be derived using the expression below;

H = m c Δt

H is the amount of energy

m is the mass

c is the specific heat

Δt is the change in temperature

H = 0.5 x 4190 x (65 - 30 )

H = 73325J