Question

Please answer

Question 3 (4 points)
If an unknown substance has a specific heat of 0.246J/gxC, is cooled by 15.5 degrees C and releases 700.0 J of enegy, what is the mass of that
sample?

Answer 1

183.6kg

Step-by-step explanation:

Given parameters:

Specific heat of the substance = 0.246J/g°C

Change in temperature = 15.5°C

Amount of energy released = 700J

Unknown:

Mass of the sample = ?

Solution:

To solve this problem we used the energy equation:

H = m c Δt

H is the energy released

m is the unknown mass

c is the specific heat

Δt is the change in temperature

Now insert the parameters and find m;

700 = m x 0.246 x 15.5

700 = 3.8m

m = 183.6kg