Answer:
768
Explanation:
Given that:
Error margin (E) = 5% = 0.05
Confidence level = 95%
Proportion p = 0.5 (since no prior value is given) ; also n1 = n2 = sample size
n = (Z / E)^2 * (1 - p)
1 - p = 1 - 0.5 = 0.5
Zscore at 95% confidence = 1.96
n = (1.96 / 0.05)^2 * 0.5
n = 39.2^2 * 0.5
n = 1536.64 * 0.5
n = 768.32
Hence, sample size = 768 SAMPLES