Answer:
Let the number of rows be x and number of students in a row be y.
Total students of the class= Number of rows × Number of students in a row
=x×y=xy
Case 1
Total number of students =(x−1)(y+3)
⇒xy=(x−1)(y+3)=xy−y+3x−3
⇒3x−y−3=0
⇒3x−y=3..... (i)
Case 2
Total number of students=(x+2)(y−3)
⇒xy=xy+2y−3x−6
⇒3x−2y=−6..... (ii)
Subtracting equation (ii) from (i),
⇒(3x−y)−(3x−2y)=3−(−6)
⇒−y+2y=3+6
⇒y=9
By substituting value of y in (i), we get
⇒3x−9=3
⇒3x=9+3=12
⇒x=4
Number of rows =x=4
Number of students in a row =y=9
Number of total students in a class =x×y=4×9=36
Explanation: