Question

What is the mass percent of oxygen (0) in SO2?

32.1 g
A.
x 100%
16.0 g + 16.0 g
(16.0 g +16g)(6.02 x 1023)
B.
100 g
16.0 g
x 100%
(32.1 g + 16.0 g + 16.0 g)
D.
(16.0 g + 16.0 g)
X 100%
(32.1 g + 16.0 g + 16.0 g)
SUIRMIT

Answer 1

16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Step-by-step explanation:

Answer 2

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Step-by-step explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%