I need help! What is the solution to the equation?

asked Oct 19, 2021 232k views

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$\displaystyle\tt\leadsto \sqrt[3]{x-1}=4$

$\displaystyle\tt\leadsto x-1 = 4^3$

$\displaystyle\tt\leadsto x = 4^3 + 1$

$\displaystyle\tt\leadsto x = 64 + 1$

$\displaystyle\leadsto \underline{\boxed{\textbf{\textsf{x = 65}}}}$

Jignesh Kheni answered Oct 24, 2021

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