Question

Help me please!, solve this integral ∫ sin^5 2x cos 2x dx

Answer 1

Explanation:

sorry, i don't know lol kgi gi yo gi yig iy iy iy i gi y8 y8

Answer 2

`\boxed{(1)/(12) \sin^6 2x + c}`

Explanation:

`\int\limits {\sin^5 2x \cos 2x} \, dx`

`= \int\limits {\sin^5 2x ~.~(1)/(2) } \, d(\sin 2x)`

`= (1)/(2) \int\limits {\sin^5 2x } \, d(\sin 2x)`

`= (1)/(2) ~.~(1)/(6) ~.~\sin^6 2x + c`

`= (1)/(12) \sin^6 2x + c`