Question

Please help..not too sure on how to work this out.

Answer 1

Answer and Step-by-step explanation:

Ok, it's basically just parts of a circle circumference and area equation. Let's start first by writing down both equations.

C = 2πr

C = πd

A = π
`r^(2)`

Now, all we have to do is plug in the values into those equations!

4. C = 2π(12) A = π(
`12^(2)`)

r = 12

d = 24 <---- (12 times 2 equals 24)

C = 24π

A = 144π <---- (12 times 12 (itself) equals 144)

5. C = π4.8 A = π(
`4.8^(2)`)

r = 2.4 <------- (4.8 divided by 2 equals 2.4)

d = 4.8

C = 4.8π

A = 23.04π <------- (4.8 times 4.8 equals 23.04)

6. 20π = 2πr A = π
`r^(2)`

r = 10 <------- (20π divided by π and divided by 2)

d = 20 <------- (20π divided by π)

C = 20π

A = 100π <------- (10 times 10 equals 100)

7. C = 2πr 81π = π
`r^(2)`

r = 9 <------- (81π divided by π and square rooted equals 9)

d = 18 <------- (9 times 2 equals 18)

C = 18π <------- (2 times 9 equals 18, times π)

A = 81π

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