Question

If a golf ball has a mass of 0.09 kg acquires a speed of 80.90 m/s when it is hit with a

force of 39.38 N. How long was the club in contact with the ball?

Answer 1

t = 0.18 s

Step-by-step explanation:

Given that,

The mas of a golf ball, m = 0.09 kg

It hits the ground with a speed of 80.90 m/s and with a force of 39.38 N.

We need to find the time of contact of the club with the ball.

The net force is given by :

`F=(m(v-u))/(t)\\\\t=(m(v-u))/(F)\\\\t=(0.09* 80.9)/(39.38 )\\\\=0.18\ s`

So, the time of contact is 0.18 s.