Question

Mr tieu spent 23 dollars on apples oranges and bananas. he bought 10 more apples than oranges and 6 fewer bananas than apples how many of each kind of fruit did he purchase if one apple costs 70 cents,one banana cost 50 cents, and one orange costs 80 cents?

Answer 1

Mr. Tieu purchased 15 apples, 5 oranges, and 9 bananas.

Step-by-step explanation:

Let's denote the number of oranges as O, the number of apples as A, and the number of bananas as B.

From the given information, we know that A = O + 10 (10 more apples than oranges) and B = A - 6 (6 fewer bananas than apples).

We can now form an equation based on the total cost and quantities of each type of fruit: 0.7A + 0.8O + 0.5B = 23 (0.7 being the cost of an apple in dollars, 0.8 being the cost of an orange, and 0.5 being the cost of a banana).

Substituting the values for A and B in terms of O, we get 0.7(O + 10) + 0.8O + 0.5(O + 10 - 6) = 23. Solving this equation, we find that O = 5, A = 15, and B = 9.