Answer:
The balanced chemical equation representing the reaction of sodium metal with oxygen gas is,
4 Na (s) + O_{2}-->2Na_{2}O(s)
4 mol Na require 1 mol O2 for complete reaction to form 2 mol Na2O
Given the moles of Na reacting = 2.90 mol Na
2 mol Na_{2}O can form from 4 mol Na as per the balanced chemical equation.
Calculating the moles of Na_{2}O that can be formed from 2.90 mol Na:
2.90 mol Na * \frac{2 mol Na_{2}O }{4 mol Na} = 1.45 mol Na_{2}O
Therefore, 1.45 mol Na_{2}O can form from 2.90 mol Na.
Step-by-step explanation:
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