Question

H^-16/h^x=1/h^24 can someone help me please

Answer 1

Given:

Consider the equation is

`(h^(16))/(h^x)=(1)/(h^(24))`

To find:

The value of x.

Solution:

We have,

`(h^(-16))/(h^x)=(1)/(h^(24))`

Using properties of exponents, we get

`h^(-16-x)=h^(-24)`
`[\because (a^m)/(a^n)=a^(m-n),a^(-n)=(1)/(a^n)]`

On comparing both sides, we get

`-16-x=-24`

Add 16 on both sides.

`-x=-24+16`

`-x=-8`

Multiply both sides by -1.

`x=8`

Therefore, the value of x is 8.