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What is the inverse of f(x)=(2x-1)^3

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Answer:


f^(-1)(x)=\frac{\sqrt[3]{x}+1}{2}}

Explanation:

Interchange x and y in the function definition and solve for y.


x=(2y-1)^3\\\\\sqrt[3]{x}=2y-1\qquad\text{take cube root}\\\\\sqrt[3]{x}+1=2y\qquad\text{add 1}\\\\y=\frac{\sqrt[3]{x}+1}{2}\qquad\text{divide by 2}\\\\\boxed{f^(-1)(x)=\frac{\sqrt[3]{x}+1}{2}}

What is the inverse of f(x)=(2x-1)^3-example-1
User Peter T Bosse II
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