19.8k views
10 votes
Solve for x
3x² - 5x + 6 = 10 - 4x​

User Sampad
by
7.9k points

2 Answers

8 votes

Answer:
-1, (4)/(3)

Explanation:


3x^(2)-5x+6=10-4x\\\\3x^(2)-x-4=0\\ \\ (x+1)(3x-4)=0 \\ \\ x=\boxed{-1, (4)/(3)}

User Robert Nubel
by
8.1k points
11 votes

Answer:

x = -1
x = 4/3

Explanation:

Hello!

First, let's convert the equation into Standard Form:
ax^2 + bx + c = 0


  • 3x^2 - 5x + 6 = 10 - 4x

  • 3x^2 - x - 4 = 0

We can solve this by factoring the quadratic. We have to find two numbers that multiply to
ac but add up to
b.

  • ac = -12
  • b = -1

The two numbers would be -4 and 3. We can expand -x to -4x + 3x, and then factor by grouping.

Factor


  • 3x^2 - x - 4 = 0

  • 3x^2 +3x - 4x - 4 = 0

  • 3x(x + 1) - 4(x + 1) = 0

  • (3x - 4)(x + 1) = 0

Use the Zero Product Property. Set each factor to zero and solve for x.

3x - 4 = 0

  • 3x = 4
  • x = 4/3

x + 1 = 0

  • x = -1

The solutions to the quadratic are -1 and 4/3.

User GEverding
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories