Question

If 760 mmHg of pressure was decreased to 458 mmHg, what would be the original volume of a gas that ended up occupying a space of 1072 mL?

Answer 1

646.02 mL

Step-by-step explanation:

The original volume can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

Since we are finding the original volume

`V_1 = (P_2V_2)/(P_1) \\`

From the question we have

`V_1 = (458 * 1072)/(760) = (490976)/(760) \\ 646.021052...`

We have the final answer as

646.02 mL

Hope this helps you