Answer:
Hypotenuse of first triangle is 7.61
Hypotenuse of second triangle is 45
Explanation:
Given that:
Triangle 1:
a = 3
b = 7
Using Pythagorean theorem;
a²+b²=c²
![(3)^2+(7)^2=c^2\\9+49=c^2\\c^2=58](https://img.qammunity.org/2021/formulas/mathematics/college/a28dpzqu86sd9x76gdafvz6oxv7za3la0r.png)
Taking square root on both sides
![√(c^2)=√(58)\\](https://img.qammunity.org/2021/formulas/mathematics/college/49omz0x4mtjrvq76shf0xs910f38hngnvg.png)
c = 7.61
Hypotenuse is 7.61
Triangle 2:
a = 27
b = 36
Using Pythagorean theorem;
a²+b²=c²
![(27)^2+(36)^2= c^2\\729+1296=c^2\\c^2=2025](https://img.qammunity.org/2021/formulas/mathematics/college/8bbbi01v71y7drq36bax8kov7le6s66jm9.png)
Taking square root on both sides
![√(c^2)=√(2025)\\](https://img.qammunity.org/2021/formulas/mathematics/college/scvuh1zqbc66ks0o3scbls2wix79kwleo2.png)
c=45
Hypotenuse is 45
Hence,
Hypotenuse of first triangle is 7.61
Hypotenuse of second triangle is 45