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Please help ASAP!!!!!!

Please help ASAP!!!!!!-example-1

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Answer:

Equation in point slope form is:
y+3=4(x+6)

Solving for y we get:
\mathbf{y=4x+21}

Explanation:

We are given:

Slope = 4

Point (-6,-3)

Point Slope form:

We need to write equation for point-slope form

The general equation of point slope form is:
y-y_1=m(x-x_1)

Where m is slope and
y_1\: and\: x_1\\ are points on the line

Now putting values of slope m= 4,
x_1=-6, y_1=-3 and finding equation


y-y_1=m(x-x_1)\\y-(-3)=4(x-(-6)\\y+3=4(x+6)

So, equation in point slope form is:
y+3=4(x+6)

Solve for y


y+3=4(x+6)\\y+3=4x+24\\y=4x+24-3\\y=4x+21

So, solving for y we get:
\mathbf{y=4x+21}

User Redab
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