Question

Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Answer 1

Equation of circle in standard form with centre (0, – 10) and radius 6.
`\mathbf{x^2+(y+10)^2=36}`

Explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is:
`(x-h)^2+(y-k)^2=r^2`

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

`(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36`

So, equation of circle in standard form with centre (0, – 10) and radius 6.
`\mathbf{x^2+(y+10)^2=36}`