Question

A man is heterozygous ( Cc ) for a recessive trait that causes a fatal illness , the mother does not carry the recessive allele ( CC ) . What is the percentage chance of their children being a carrier the trait ?

A.50%
B.25%
C.75%
D.0%
​

Answer 1

50% using a punnet square

Answer 2

Answer: A. 50%

Explanation: If you create a Punnett Square and cross the 2 genotypes, out of the 4 possibilities, 2 will be CC and 2 will be Cc.