Question

Using the balanced equation below,

how many grams of zinc would be
required to produce 9.65 g of zinc
hydroxide?
Zn + 2MnO2 + H20 → Zn(OH)2 + Mn203

Please help I need it for a test

Answer 1

Mass = 6.538 g

Step-by-step explanation:

Given data:

Mass of zinc hydroxide produced = 9.65 g

Mass of zinc required = ?

Solution:

Chemical equation:

Zn + 2MnO₂ + H₂O → Zn(OH)₂ + Mn₂O₃

Number of moles of zinc hydroxide:

Number of moles = mass/molar mass

Number of moles = 9.65 g/ 99.42 g/mol

Number of moles = 0.1 mol

now we will compare the moles of zinc and zinc hydroxide,

Zn(OH)₂ : Zn

1 : 1

0.1 : 0.1

Mass of zinc required:

Mass = number of moles × molar mass

Mass = 0.1 mol × 65.38 g/mol

Mass = 6.538 g

Answer 2

Answer: 6.35

Step-by-step explanation: