Answer:
one number = 3 ; other number = 6
(x = 3 ; y = 6)
Explanation:
here is the written problem in an algebraic form:
(x is one number, y is the other number)
x = y - 3 {"if one number is 3 subtracted from the other..."}
x + y = 9 {"The sum of two numbers is 9"}
substitute [x = y-3] into [x + y =9]
x + y = 9 ; {x = y - 3}
(y - 3) + y = 9 [substitute known x-value into equation]
y - 3 + y = 9
+ 3 + 3 [add 3 to isolate y]
2y = 12
÷2 ÷2 [divide by 2 to find y]
y = 6
Now, by plugging our y-value (6) into one of the equations:
x + y = 9
x + 6 = 9 [substitute the y-value, which we know is 6]
-6 -6
x = 3
so, one number is 3, and the other number is 6