Question

What is the solution set for this quadratic equation 2(x-3)^2-4=28

Answer 1

Answer: x₁=7, x₂=-1

Explanation:

(x-3)^2= x^2-6x+9

2(x^2-6x+9)=28+4

x^2-6x+9=16

x^2-6x-7=0

you use the quadratic equation will give you 2 roots,

x₁=7, x₂=-1

Answer 2

4(x-3)-4=28
4x-12-4=28
4x-16=28
4x=28+16
4x=44
x=11