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If the E°cell value = +0.46V and E°(Ag+/Ag) = +0.80V calculate the E° value for ( Cu2+/Cu)? electrochemical cell: Cu/Cu2+//Ag+/Ag use the formula: E°cell = E°reduced - E°oxidized
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2 votes
If the E°cell value = +0.46V and E°(Ag+/Ag) = +0.80V

calculate the E° value for ( Cu2+/Cu)?

electrochemical cell:
Cu/Cu2+//Ag+/Ag

use the formula:

E°cell = E°reduced - E°oxidized

User Avanti
by
5.9k points

1 Answer

10 votes

Answer:

0.34

Step-by-step explanation:

Cu>>>Cu2+(oxidation number increases)[Oxidation occurs]

Ag+>>>Ag(Oxidation number decreases) [Reduction occurs]

E°=0.80-0.46

=0.34V

User KCP
by
5.8k points
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