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John is pushing (horizontally) on a 100 kg (Fw = 980N) bench with an unknown force. If the coefficient of static friction is 0.20 and the acceleration is 1.84m/s/s, what is the applied force?

User Patwie
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1 Answer

7 votes

Answer:

1176N

Step-by-step explanation:

Given parameters:

Mass of bench = 100kg

Forward force = 980N

Coefficient of static friction = 0.2

Acceleration = 1.84m/s²

Unknown:

Magnitude of the applied force =?

Solution:

Frictional force is a force that opposes motion, for a body to move, the applied force must be greater than the frictional force;

The Force applied;

Force applied = Frictional force + Weight of the body

Frictional force = umg

u is the coefficient of static friction

m is the mass

g is the acceleration due to gravity

Force applied = 0.2 x 100 x 9.8 + 980 = 1176N

User Kshitij Kohli
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