Question

The sum of three times a first number and twice a second number is 14. If the second number is subtracted from twice the first number, the result is 7. Find the numbers. The sum of three times a first number and twice a second number is 14. If the second number is subtracted from twice the first number , the result is 7 . Find the numbers . Or as points ​

Answer 1

Answer: 4, 1

Explanation:

Let the First Number be ‘x’
Let the Second Number be ‘y’

Framing 2 Equations :-

=> 3x + 2y = 14 (Eq. 1)
=> 2x - y = 7 (Eq. 2)

Multiplying Eq. 2 by 2 :-

=> 4x - 2y = 14 (Eq. 3)

Adding Eq. 1 and Eq. 3 we get :-

7x = 14 + 14
7x = 28
x = 28/7
=> x = 4

Therefore, x = 4

Substitute value of ‘x’ in Eq. 1 :-

3x + 2y = 14
3(4) + 2y = 14
12 + 2y = 14
2y = 14 - 12
2y = 2
y = 2/2
=> y = 1

Therefore, y = 1

Hence,
First Number = 4
Second Number = 1