Question

Bobby hit the wrong lever and as a result the factory produced way too many cheese puffs. If the factory managers decide to to give away 1/3 of 1/9 of a ton away as samples, what fraction of a ton did they give away? Make sure you answer is fully reduced.

Answer 1

Given:

The factory managers decide to to give away
`(1)/(3)` of
`(1)/(9)` of a ton away as samples.

To find:

what fraction of a ton did they give away?

Solution:

According to the question, the factory managers decide to to give away
`(1)/(3)` of
`(1)/(9)` of a ton away as samples. So,

`\text{Samples}=(1)/(3)\left((1)/(9)(1\text{ ton})\right)`

`\text{Samples}=(1)/(3)* (1)/(9)* (1\text{ ton})`

`\text{Samples}=(1)/(27)* (1\text{ ton})`

`\text{Samples}=(1)/(27)(1\text{ ton})`

So, samples is
`(1)/(27)` of a ton.

Therefore, they give away
`(1)/(27)` of a ton as samples.