Question

Your company makes game parts using 3-D printers. One customer wants a circular game coin that is 2.0 centimeter across and 0.5 centimeters thick. You need to estimate the of plastic you will need for each arch of 50 coins. How many cubic centimeters is that, rounded up if necessary to be a multiple of 10 cubic centimeters?

Answer 1

80 cm^3

Explanation:

The computation of the number of cubic centimeters rounded up to 10 cubic centimeter is shown below

For any type coin,

r = d ÷ 2

= 2 ÷ 2

= 1 cm

l = 0.5cm

For making 1 coin, the plastic required would be = Volume of coin

= πlr^2

= 3.14 × 0.5 × 1 × 1

= 1.57cm^3

Now For 50 coins,

Plastic needed is

= 50 × 1.57

= 78.5cm^3

= 80 cm^3