Question

15 kg of ice at 0°C is heated to water of temperature 20°C. What is the amount of heat required if the specific latent heat of ice fusion is 335 kJ/kg and the specific heat capacity of water is 4.19kJ/kg/°C?

Answer 1

6282 kJ

Step-by-step explanation:

Given that:

The mass (m) = 15 kg

The specific latent heat of ice fusion
`h_(fg)_(ice)` = 335 kJ/kg

The specific heat capacity of water = 4.19 kJ/kg.c

The initial temperature of the ice
`T_i`= 0° C

The final temperature of the water
`T_f` = 20° C

To find the needed amount of heat to convert 0° C ice to 20° C of water.

To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert 0° C water to 20° C water.

Heat required =
`m * h_(fg)_(ice)+ m * c_(water) * \Delta T`

Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)

Heat required = 5025 + 62.85 × 20

Heat required = 5025 + 1257

Heat required = 6282 kJ