Given:
Total students = 6,000
Students taking honors courses = 1,500
Students preferring basketball = 1,800
Students in both = 450
To find:
Whether the two events "taking honors courses" and "preferring basketball" are independent or not?
Solution:
Let as consider the following events.
A : Taking honors courses
B : Preferring basketball
: Both
We know that,
![\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/wy85jy1lfgwt8smszp3drksxes2dlrj65o.png)
Using this formula, we get
![P(A)=(1500)/(6000)=0.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/u4skwoqpl8n0n53e5uopaog8kshw5fl47i.png)
![P(B)=(1800)/(6000)=0.30](https://img.qammunity.org/2021/formulas/mathematics/high-school/i3tlbtal70sqfeyp3ck6t13c474pdz4nx7.png)
![P(A\cap B)=(450)/(6000)=0.075](https://img.qammunity.org/2021/formulas/mathematics/high-school/it4igtaaiwc5bbfy4zx216kt8ufe1kjdj6.png)
Two evens are independent if
![P(E_1\cap E_2)P(E_1)\cdot P(E_2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/k1i1d6camdjfw6b5s4ktolkevdr9nun6q4.png)
Now,
![P(A)\cdot P(B)=0.25* 0.30](https://img.qammunity.org/2021/formulas/mathematics/high-school/uu31ht12frfds7visihkz3q5kkaro127qg.png)
![P(A)\cdot P(B)=0.075](https://img.qammunity.org/2021/formulas/mathematics/high-school/bdsjd34zov7h86lta6ut3u2g02onj80eb2.png)
![P(A)\cdot P(B)=P(A\cap B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qrii5o3qc3bkvsm58szx6q7errrogoi8hz.png)
So, the events A and B are intendent because
![((1500)/(6000))((1800)/(6000))=(450)/(6000)](https://img.qammunity.org/2021/formulas/mathematics/high-school/agfftw9n8sawdhscmp09bg9lrparmarwk4.png)
Therefore, the correct option is D.