Question

There are 4.9875 mol C, 7.9802 mol H,

and 2.00 mol O in the sample.
Divide each by the smallest number of
moles. What is the ratio for the C?

[?] C [ ]H[ ]0

Answer 1

So, in 1 mol there are 6.02x10^23 atoms, regardless of the susbtance, only the weight of the mol changes. Doing a simple rule of 3 we can get many of the answers to your questions.

Step-by-step explanation:

1mol of Ar → 6.02x10^23 atoms

0.25 mol → X

So now what we do is (0.25mol * 6.02x10^23 atoms)/1 mol = X

That gives us 1.505x10^23 atoms in 0.25 mol of Ar.

For this I'm guessing you mean the stable form of oxygen, O2. The Avogadro constant stays well, constant.

1 mol of O2 → 6.02x10^23 molecules

1.0×10^-4 mol of O2 → X molecules

So you can do (1.0×10^-4 * 6.02x10^23) / 1mol = X

(I feel like this is homework, so i will help you, but not give you all the answer, will be good practice to try yourself) :)

For this you need to know the weight of a mol of Be. Luckily the periodic table gives us that number. The number under each element is the weight in grams of 1 mol .

Answer 2

C- 2.48925 H- 3.9901 O- 1

Step-by-step explanation:

Read the instructions