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Calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral​

1 Answer

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Moles of benzene

  • 70/90=7/9=0.8mol

moles of CCl_4

  • 30/154
  • 0.2mol

Now


\\ \rm\Rrightarrow \chi_(C_6H_6)


\\ \rm\Rrightarrow (\chi_(C_6H_6))/(\chi_(sol^n))


\\ \rm\Rrightarrow (0.8)/(0.8+0.2)


\\ \rm\Rrightarrow (0.8)/(1)


\\ \rm\Rrightarrow 0.8

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