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A boat is carried with the current at an angle of 43 degrees to the shore. if the river is approx. 15 meters wide, how far does the boat travel before reaching the opposite side of the shore

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Answer:

22 m

Explanation:

The computation of the how much far does the boat travel is as follows:

sin 43 degrees = 15 ÷ d

d = 15 ÷sin 43 degrees

= 15 ÷ 0.6820

= 21.99

= 22 m

Hence, the how much far does the boat travel is 22 m

We simply applied the above formula so that the correct value could come

The same is to be considered

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