Question

During a reaction, the enthalpy of formation of an intermediate is -286

kj/mol. during the reaction, 2 moles of the intermediate are produced. what
is the enthalpy value for this step of the reaction?
a:286 kj
b:-286 kj
c:-572 kj
d:572 kj

Answer 1

C.) -572 kJ

Step-by-step explanation:

The enthalpy of formation is a ratio consisting of enthalpy and moles. Since you have been given the enthalpy of formation and moles, you can use the ratio to find the enthalpy.

Enthalpy of Formation (kJ/mol) = Enthalpy (kJ) / moles

-286 kJ/mol = Enthalpy (kJ) / 2 moles <---- Plug in variables

-572 = Enthalpy (kJ) <---- Multiply both sides by 2