Starting with one circle there are no intersections
Two circles have 2 intersections
Three circles have 4 extra intersections so the total is 6
The nth circle will cross all the previous circles twice = 2(n-1) extra intersections
The greatest number of unique intersections = 0 + 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 = 90