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A sample of a gas at room temperature occupies a volume of 24.0 L at a pressure of 602 torr . If the pressure changes to 3010 torr , with no change in the temperature or moles of gas, what is the new volume, V2

User Tahamv
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1 Answer

4 votes

Answer:

V₂ = 4.80 L

Step-by-step explanation:

Because you are dealing solely with pressure and volume, you can find the new volume using the Boyle's Law equation. The general equation looks like this:

P₁V₁ = P₂V₂

In this form, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the new pressure and volume. You have been given all of the variables but V₂. Therefore, by plugging these values into the equation, you can simplify to find your answer.

P₁ = 602 torr V₁ = 24.0 L

P₂ = 3010 torr V₂ = ?

P₁V₁ = P₂V₂ <---- Boyle's Law equation

(602 torr)(24.0L) = (3010 torr)V₂ <---- Plug variables into equation

144448 = (3010 torr)V₂ <---- Multiply 602 and 24.0

4.80 = V₂ <---- Divide both sides by 3010

User Dmitriy Lezhnev
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