Question

1.Find the eqn of line passing through the point of intersection of lines 5x+y=7 and 3y=4x-5 and parallel to the line 2x-y=3​

Answer 1

y = 2x - 259/115 [slope-intercept]

-230x + 115y = -259 [standard form]

Explanation:

First make sure both of the intersecting lines are in standard form: Ax + By = C.

Then, multiply one of the equations by a certain quantity so one of the variables can be canceled out.

For example:

given 5x + y = 7, and 3y = 4x - 5.

You can rearrange the second equation since it is not currently in standard form.

So all we need to do is subtract both sides by 4x since that will leave the constant of C by itself.

3y = 4x - 5 → 3y - 4x = 4x - 5 - 4x →

3y - 4x = -5.

Now adding a negative number is the same as subtracting a positive number, this is because subtraction is the opposite of adding.

So 3y - 4x = -5 = 3y + (-4x) = -5 →

-4x + 3y = -5