Question

A 45 kg wagon is being pulled with a rope that makes an angle of 38 degrees with the horizontal. The applied force is 410 N and the coefficient of kinetic friction between the wagon and the ground is 0.18.

Answer 1

7.35m/s²

Step-by-step explanation:

From the question we are not told what to find but we can as well find the acceleration of the wagon.

According to newton second law of motion

`\sum F_x = ma_x\\Fm - Ff = ma_x\\Fm - \mu R = ma_x\\Fm- \mu mg = ma_x\\`

Fm is the moving force = 410N

`\mu` is the coefficient of friction = 0.18

m is the mass = 45kg

g is the acceleration dur to gravity = 9.8m/s²

a is the acceleration of the wagon

Substitute the given data into the equation ang get ax

`Fm- \mu mg = ma_x\\410 - (0.18)(9.8)(45) = 45a_x\\410 - 79.38 = 45a_x\\330.62 = 45a_x\\a_x = 330.62/45\\a_x = 7.35m/s^2\\`

Hence the acceleration of the wagon is 7.35m/s²