Answer: 25%
Explanation:
Given: A rectangle has length 4 inches and width 2 inches.
Area = Length x width
= 4 inches x 2 inches
= 8 square inches
If length is reduced by 50% , then length
![=0.5*4=2\text{ inches}](https://img.qammunity.org/2021/formulas/mathematics/high-school/fzd26wbwfnrb4kzpp7rr4x4kghxl7d8eap.png)
If width is reduced by 50% , then length
![=0.5*2=1\text{ inch}](https://img.qammunity.org/2021/formulas/mathematics/high-school/yel3a9nev81er6pysr2lftcz2zwk2orqdc.png)
Reduced area = (reduced length) x (reduced width)
= 2 inches x 1 inch
= 2 square inches
The percentage of the area of the rectangle be reduced :-
![\frac{\text{Reduced area}}{\text{Original area}}*100 \\\\=(2)/(8)*100\% \\\\=25\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/mdyn5qm0ec8cqatteqvz0578nrtol71iji.png)
Hence, the percent of the area of the rectangle be reduced = 25%