Question

A 1 kg block sliding to the right on a level, frictionless surface with a speed

of 2 m/s collides and sticks to a second 1 kg block sliding to the left. after
the collision, the blocks are motionless. what was the speed of the second
1 kg block before the collision?

Answer 1

2m.s¹ left

Step-by-step explanation:

( Mblock1 x V initial ) + (Mblock2 x V initial) = ( M1 +M2)×0

(1×2) + (1× V initial) = 0

V initial = -2

* I consider right as positive(+)*